Subtract 6 from both sides, and then divide by $\displaystyle-{4}\usepackage{cmbright}\Huge\$ :

$\displaystyle-{4}{y}+{6}-{6}<-{2}-{6}\usepackage{cmbright}\Huge\$ or $\displaystyle-{4}{y}<-{8}\usepackage{cmbright}\Huge\$

$\displaystyle\frac{{-{4}{y}}}{{-{{4}}}}>\frac{{-{8}}}{{-{{4}}}}\usepackage{cmbright}\Huge\$ or $\displaystyle{y}>{2}\usepackage{cmbright}\Huge\$