After simplifying the following expression, the coefficient of the $\displaystyle{{m}}^{{2}}{n}\usepackage{cmbright}\Huge\$ term will be _____.

$\displaystyle{6}{m}{{n}}^{{2}}+{3}{{m}}^{{2}}+{16}{{m}}^{{2}}{n}-{6}{{m}}^{{2}}-{5}{n}{{m}}^{{2}}\usepackage{cmbright}\Huge\$