Correct. Apply the exponent 4 to each factor individually: $\displaystyle\frac{{{{\left({{x}}^{{7}}\right)}}^{{4}}{{\left({{y}}^{{3}}\right)}}^{{4}}}}{{{{\left({3}\right)}}^{{4}}{{\left({{z}}^{{2}}\right)}}^{{4}}}}\usepackage{cmbright}\Huge\$

Simplify, using the power rule: $\displaystyle\frac{{{{x}}^{{{7}\cdot{4}}}{{y}}^{{{3}\cdot{4}}}}}{{{81}{{z}}^{{{2}\cdot{4}}}}}=\frac{{{{x}}^{{28}}{{y}}^{{12}}}}{{{81}{{z}}^{{8}}}}\usepackage{cmbright}\Huge\$