Correct. First apply the exponent 3 to each factor in the numerator: $\displaystyle\frac{{{{2}}^{{3}}{{s}}^{{3}}}}{{{s}}^{{2}}}=\frac{{{8}{{s}}^{{3}}}}{{{s}}^{{2}}}\usepackage{cmbright}\Huge\$

Use the Quotient Rule: $\displaystyle{8}{{s}}^{{{\left({3}-{2}\right)}}}={8}{{s}}^{{1}}={8}{s}\usepackage{cmbright}\Huge\$

Evaluate the expression, using $\displaystyle-{1}\usepackage{cmbright}\Huge\$ in place of s: $\displaystyle{8}{\left(-{1}\right)}=-{8}\usepackage{cmbright}\Huge\$