Correct. Substitute $\displaystyle-{3}\usepackage{cmbright}\Huge\$ for a:

$\displaystyle{3}{{\left(-{3}\right)}}^{{2}}-{4}{\left(-{3}\right)}+{1}={3}{\left({9}\right)}-{\left(-{12}\right)}+{1}={27}+{12}+{1}={40}\usepackage{cmbright}\Huge\$