Find the missing part of the simplified expression.

$\displaystyle{{\left(\frac{{{{x}}^{{5}}{{y}}^{{8}}}}{{{2}{{z}}^{{3}}}}\right)}}^{{6}}=\frac{{{{x}}^{{30}}{{y}}^{{48}}}}{{?{{z}}^{{18}}}}\usepackage{cmbright}\Huge\$