Correct. First apply the exponent 2 to each factor in the numerator: $\displaystyle\frac{{{{5}}^{{2}}{{s}}^{{2}}}}{{{s}}^{{3}}}=\frac{{{25}{{s}}^{{2}}}}{{{s}}^{{3}}}\usepackage{cmbright}\Huge\$

Use the quotient rule: $\displaystyle{25}{{s}}^{{{\left({2}-{3}\right)}}}={25}{{s}}^{{-{{1}}}}=\frac{{25}}{{s}}\usepackage{cmbright}\Huge\$

Evaluate the expression, using $\displaystyle-{1}\usepackage{cmbright}\Huge\$ in place of s: $\displaystyle\frac{{25}}{{-{1}}}=-{25}\usepackage{cmbright}\Huge\$