Incorrect. A binomial in the form $\displaystyle{{a}}^{{3}}+{{b}}^{{3}}\usepackage{cmbright}\Huge\$ can be factored as $\displaystyle{\left({a}+{b}\right)}{\left({{a}}^{{2}}-{a}{b}+{{b}}^{{2}}\right)}\usepackage{cmbright}\Huge\$ . Since $\displaystyle{{x}}^{{3}}+{27}={{x}}^{{3}}+{{3}}^{{3}}\usepackage{cmbright}\Huge\$ , in this expression $\displaystyle{a}={x}\usepackage{cmbright}\Huge\$ and $\displaystyle{b}={3}\usepackage{cmbright}\Huge\$ .