$\displaystyle{{x}}^{{3}}-{1},{000}={{x}}^{{3}}-{{10}}^{{3}}\usepackage{cmbright}\Huge\$ , and a binomial in the form $\displaystyle{{a}}^{{3}}-{{b}}^{{3}}\usepackage{cmbright}\Huge\$ can be factored as $\displaystyle{\left({a}-{b}\right)}{\left({{a}}^{{2}}+{a}{b}+{{b}}^{{2}}\right)}\usepackage{cmbright}\Huge\$ . The missing number is the value of $\displaystyle{{b}}^{{2}}\usepackage{cmbright}\Huge\$ , but you found $\displaystyle{{b}}^{{3}}\usepackage{cmbright}\Huge\$ . Whenever you factor, remember to check your answer by multiplying the factors back together.