Correct. First add 64 to both sides of the equation to make one side equal to 0. The quadratic expression is a perfect square trinomial.

$\displaystyle{{n}}^{{2}}-{16}{n}+{64}={0}\usepackage{cmbright}\Huge\$

$\displaystyle{\left({n}-{8}\right)}{\left({n}-{8}\right)}={0}\usepackage{cmbright}\Huge\$

$\displaystyle{n}-{8}={0}\usepackage{cmbright}\Huge\$

$\displaystyle{n}={8}\usepackage{cmbright}\Huge\$