If $\displaystyle{x}={4}\usepackage{cmbright}\Huge\$ is one solution to the equation $\displaystyle{\left({x}-{4}\right)}{\left({x}-{6}\right)}={0}\usepackage{cmbright}\Huge\$ , what is the other solution?

The other solution is $\displaystyle{x}=\usepackage{cmbright}\Huge\$ _____.