Correct. $\displaystyle{5}{{x}}^{{2}}+{17}{x}+{14}={5}{{x}}^{{2}}+{10}{x}+{7}{x}+{14}={\left({5}{{x}}^{{2}}+{10}{x}\right)}+{\left({7}{x}+{14}\right)}\usepackage{cmbright}\Huge\$

$\displaystyle={5}{x}{\left({x}+{2}\right)}+{7}{\left({x}+{2}\right)}={\left({x}+{2}\right)}{\left({5}{x}+{7}\right)}\usepackage{cmbright}\Huge\$

The value of b is 7.