Incorrect. $\displaystyle{5}{{x}}^{{2}}+{17}{x}+{14}={\left({5}{{x}}^{{2}}+{10}{x}\right)}+{\left({7}{x}+{14}\right)}\usepackage{cmbright}\Huge\$ . Factor out the common factor in each pair. Then factor out the common binomial factor. The correct answer is 7.