A binomial in the form $\displaystyle{{a}}^{{3}}+{{b}}^{{3}}\usepackage{cmbright}\Huge\$ can be factored as $\displaystyle{\left({a}+{b}\right)}{\left({{a}}^{{2}}-{a}{b}+{{b}}^{{2}}\right)}\usepackage{cmbright}\Huge\$ .

$\displaystyle{64}{{x}}^{{3}}+{27}={{\left({4}{x}\right)}}^{{3}}+{{3}}^{{3}}={\left({4}{x}+{3}\right)}{\left({{\left({4}{x}\right)}}^{{2}}-{4}{x}\cdot{3}+{{3}}^{{2}}\right)}={\left({4}{x}+{3}\right)}{\left({16}{{x}}^{{2}}-{12}{x}+{9}\right)}\usepackage{cmbright}\Huge\$