Correct. Substitute $\displaystyle{y}+{1}\usepackage{cmbright}\Huge\$ for x in the second equation: $\displaystyle{3}{y}={y}+{1}+{7}\usepackage{cmbright}\Huge\$

Simplify and solve for y: $\displaystyle{3}{y}={y}+{8}\usepackage{cmbright}\Huge\$ , $\displaystyle{2}{y}={8}\usepackage{cmbright}\Huge\$ , $\displaystyle{y}={4}\usepackage{cmbright}\Huge\$

Substitute this value for y back into the first equation: $\displaystyle{x}={4}+{1}={5}\usepackage{cmbright}\Huge\$