In order for the ordered pair to be a solution to the system it must make both equations true. While (5, 4) is a solution to the first equation, it is not a solution to the second equation. The correct answer is: $\displaystyle{\left({5},{4}\right)}\usepackage{cmbright}\Huge\$ is a solution to one equation but not the other one, so it is not a solution to the system.