Substitute $\displaystyle{\left(-{6},{4}\right)}\usepackage{cmbright}\Huge\$ for x and y:

$\displaystyle{4}<{3}{\left(-{6}\right)}-{4}\usepackage{cmbright}\Huge\$ or $\displaystyle{4}<-{18}-{4}\usepackage{cmbright}\Huge\$

This is a false statement, so $\displaystyle{\left(-{6},{4}\right)}\usepackage{cmbright}\Huge\$ is not a solution to this inequality. The correct answer is $\displaystyle{y}\ge-\frac{{1}}{{3}}{x}+{2}\usepackage{cmbright}\Huge\$ .