Correct. Multiply the first equation by 3 and the second equation by 2:

$\displaystyle{12}{x}+{6}{y}={18}\usepackage{cmbright}\Huge\$

$\displaystyle{20}{x}-{6}{y}={110}\usepackage{cmbright}\Huge\$

Add the equations to get: $\displaystyle{32}{x}={128}\usepackage{cmbright}\Huge\$

Solve for $\displaystyle{x}\usepackage{cmbright}\Huge\$ to get $\displaystyle{x}={4}\usepackage{cmbright}\Huge\$ , and substitute into the first equation:

$\displaystyle{4}{\left({4}\right)}+{2}{y}={6}\usepackage{cmbright}\Huge\$ or $\displaystyle{16}+{2}{y}={6}\usepackage{cmbright}\Huge\$ , so $\displaystyle{2}{y}=-{10}\usepackage{cmbright}\Huge\$ and $\displaystyle{y}=-{5}\usepackage{cmbright}\Huge\$