Correct. Let x, y, and z be the amounts invested in the three accounts. Then

$\displaystyle{x}+{y}+{z}={2},{000}\usepackage{cmbright}\Huge\$

$\displaystyle{4}{x}={z}\usepackage{cmbright}\Huge\$ or $\displaystyle{4}{x}-{z}={0}\usepackage{cmbright}\Huge\$

$\displaystyle{0.03}{x}+{0.06}{y}+{0.08}{z}={135}\usepackage{cmbright}\Huge\$

Multiply by 100 to get rid of the decimals: $\displaystyle{3}{x}+{6}{y}+{8}{z}={13},{500}\usepackage{cmbright}\Huge\$

Multiply the first by $\displaystyle-{6}\usepackage{cmbright}\Huge\$ and add it to the new third: $\displaystyle-{3}{x}+{2}{z}={1},{500}\usepackage{cmbright}\Huge\$

Multiply the second equation by 2 and add to the above: $\displaystyle{5}{x}={1},{500}\usepackage{cmbright}\Huge\$ or $\displaystyle{x}={300}\usepackage{cmbright}\Huge\$

From the second equation: $\displaystyle{z}={1},{200}\usepackage{cmbright}\Huge\$ and from the first equation: $\displaystyle{y}={500}\usepackage{cmbright}\Huge\$