Correct.

$\displaystyle{y}=\frac{{k}}{{x}}\usepackage{cmbright}\Huge\$ , so $\displaystyle{24}=\frac{{k}}{{4}}\usepackage{cmbright}\Huge\$ , so $\displaystyle{k}={96}\usepackage{cmbright}\Huge\$

$\displaystyle{y}=\frac{{k}}{{x}}\usepackage{cmbright}\Huge\$ , so $\displaystyle{y}=\frac{{96}}{{3}}\usepackage{cmbright}\Huge\$ , so $\displaystyle{y}={32}\usepackage{cmbright}\Huge\$