You are given $\displaystyle{P}={12},{000}\usepackage{cmbright}\Huge\$ , $\displaystyle{r}={0.02}\usepackage{cmbright}\Huge\$ , $\displaystyle{m}={2}\usepackage{cmbright}\Huge\$ , and $\displaystyle{t}={5}\usepackage{cmbright}\Huge\$ . Substituting into the formula gives you:

$\displaystyle{A}={12},{000}{{\left({1}+\frac{{0.02}}{{2}}\right)}}^{{{2}\cdot{5}}}={12},{000}{{\left({1.01}\right)}}^{{10}}\approx{12},{000}{\left({1.1046221}\right)}\usepackage{cmbright}\Huge\$

So $\displaystyle{A}\approx{13},{255.47}\usepackage{cmbright}\Huge\$ .