Evaluate $\displaystyle{{3}}^{{2}}\usepackage{cmbright}\Huge\$ : $\displaystyle{{9}}^{{{8}-{3}{x}}}={{9}}^{{{2}{x}-{2}}}\usepackage{cmbright}\Huge\$

Because both exponential expressions have the same base, their exponents must be equal. Write a new equation that sets the exponents equal to each other:

$\displaystyle{8}-{3}{x}={2}{x}-{2}\usepackage{cmbright}\Huge\$

Solve the linear equation as you normally would: $\displaystyle{10}-{3}{x}={2}{x},{10}={5}{x},{2}={x}\usepackage{cmbright}\Huge\$