You may have mistakenly used a $\displaystyle{{45}}^{\circ}-{{45}}^{\circ}-{{90}}^{\circ}\usepackage{cmbright}\Huge\$ triangle and found $\displaystyle{{\cot{{45}}}}^{\circ}\usepackage{cmbright}\Huge\$ .

Refer to the $\displaystyle{{30}}^{\circ}-{{60}}^{\circ}-{{90}}^{\circ}\usepackage{cmbright}\Huge\$ triangle. From there you can see that $\displaystyle{{\cos{{30}}}}^{\circ}=\frac{\sqrt{{3}}}{{2}}\usepackage{cmbright}\Huge\$ . It follows that $\displaystyle{x}={{30}}^{\circ}\usepackage{cmbright}\Huge\$ .