Correct. Use the rules of exponents to simplify the expression.

$\displaystyle{{\left({4}{{c}}^{{2}}\right)}}^{{\frac{{1}}{{2}}}}={{4}}^{{\frac{{1}}{{2}}}}\cdot{{c}}^{{\frac{{2}}{{2}}}}={{\left({2}\cdot{2}\right)}}^{{\frac{{1}}{{2}}}}\cdot{{c}}^{{1}}={{\left({{2}}^{{2}}\right)}}^{{\frac{{1}}{{2}}}}\cdot{c}={{2}}^{{\frac{{2}}{{2}}}}\cdot{c}={2}{c}\usepackage{cmbright}\Huge\$