Correct.

$\displaystyle\frac{{{3}{{x}}^{{2}}+{7}{x}+{2}}}{{{3}{{x}}^{{2}}-{8}{x}-{3}}}=\frac{{{\left({3}{x}+{1}\right)}{\left({x}+{2}\right)}}}{{{\left({3}{x}+{1}\right)}{\left({x}-{3}\right)}}}=\frac{{{3}{x}+{1}}}{{{3}{x}+{1}}}\cdot\frac{{{x}+{2}}}{{{x}-{3}}}\usepackage{cmbright}\Huge\$

$\displaystyle={1}\cdot\frac{{{x}+{2}}}{{{x}-{3}}}\usepackage{cmbright}\Huge\$

The question mark stands for the number 2.