Correct. The least common denominator is $\displaystyle{p}\cdot{3}{q}={3}{p}{q}\usepackage{cmbright}\Huge\$ . Rewrite each fraction to have this denominator:

$\displaystyle\frac{{4}}{{p}}-\frac{{2}}{{{3}{q}}}=\frac{{4}}{{p}}\cdot\frac{{{3}{q}}}{{{3}{q}}}-\frac{{2}}{{{3}{q}}}\cdot\frac{{p}}{{p}}=\frac{{{12}{q}}}{{{3}{p}{q}}}-\frac{{{2}{p}}}{{{3}{p}{q}}}=\frac{{{12}{q}-{2}{p}}}{{{3}{p}{q}}}\usepackage{cmbright}\Huge\$

The missing term is $\displaystyle{12}{q}\usepackage{cmbright}\Huge\$ .