Correct. Factor the coefficient 9 into $\displaystyle{3}\cdot{3}\usepackage{cmbright}\Huge\$ : $\displaystyle\sqrt{{{3}\cdot{3}\cdot{{x}}^{{10}}}}\usepackage{cmbright}\Huge\$

Factor the variable into squares: $\displaystyle\sqrt{{{3}\cdot{3}\cdot{{x}}^{{2}}\cdot{{x}}^{{2}}\cdot{{x}}^{{2}}\cdot{{x}}^{{2}}\cdot{{x}}^{{2}}}}\usepackage{cmbright}\Huge\$

Write $\displaystyle{3}\cdot{3}\usepackage{cmbright}\Huge\$ as $\displaystyle{{3}}^{{2}}\usepackage{cmbright}\Huge\$ and separate into individual radicals: $\displaystyle\sqrt{{{{3}}^{{2}}}}\cdot\sqrt{{{{x}}^{{2}}}}\cdot\sqrt{{{{x}}^{{2}}}}\cdot\sqrt{{{{x}}^{{2}}}}\cdot\sqrt{{{{x}}^{{2}}}}\cdot\sqrt{{{{x}}^{{2}}}}\usepackage{cmbright}\Huge\$

Simplify: $\displaystyle{3}\cdot{\left|{x}\right|}\cdot{\left|{x}\right|}\cdot{\left|{x}\right|}\cdot{\left|{x}\right|}\cdot{\left|{x}\right|}={3}{{x}}^{{5}}\usepackage{cmbright}\Huge\$