Correct. Rewrite in standard form by adding 49 to both sides: $\displaystyle{{x}}^{{2}}-{14}{x}+{49}={0}\usepackage{cmbright}\Huge\$

Use the Quadratic Formula, $\displaystyle{x}=\frac{{-{b}\pm\sqrt{{{{b}}^{{2}}-{4}{a}{c}}}}}{{{2}{a}}}\usepackage{cmbright}\Huge\$ , with $\displaystyle{a}={1},{b}=-{14}\usepackage{cmbright}\Huge\$ , and $\displaystyle{c}={49}\usepackage{cmbright}\Huge\$ :

$\displaystyle{x}=\frac{{-{\left(-{14}\right)}\pm\sqrt{{{{\left(-{14}\right)}}^{{2}}-{4}{\left({1}\right)}{\left({49}\right)}}}}}{{{2}\cdot{1}}}=\frac{{{14}\pm\sqrt{{{196}-{196}}}}}{{2}}=\frac{{14}}{{2}}={7}\usepackage{cmbright}\Huge\$