You probably substituted 1 for b in the Quadratic Formula. The first step is to subtract x from both sides: $\displaystyle{{x}}^{{2}}-{x}+\frac{{5}}{{4}}={0}\usepackage{cmbright}\Huge\$

Now substitute $\displaystyle{a}={1},{b}=-{1}\usepackage{cmbright}\Huge\$ , and $\displaystyle{c}=\frac{{5}}{{4}}\usepackage{cmbright}\Huge\$ into $\displaystyle{x}=\frac{{-{b}\pm\sqrt{{{{b}}^{{2}}-{4}{a}{c}}}}}{{{2}{a}}}\usepackage{cmbright}\Huge\$