Correct. In this equation, $\displaystyle{a}={2},{b}=-{5}\usepackage{cmbright}\Huge\$ , and $\displaystyle{c}={3}\usepackage{cmbright}\Huge\$ .

$\displaystyle{{b}}^{{2}}-{4}{a}{c}={{\left(-{5}\right)}}^{{2}}-{4}{\left({2}\right)}{\left({3}\right)}={25}-{24}={1}\usepackage{cmbright}\Huge\$

Because the discriminant is positive, there are two real solutions.