Correct. Because $\displaystyle{c}={9}\usepackage{cmbright}\Huge\$ , the constant term will be 9. If we rewrite the equation with the right side equal to 0, the left side will have the term 9. To get 0 on the right side, add the opposite of $\displaystyle{x}-{2}-{3}{{x}}^{{2}}\usepackage{cmbright}\Huge\$ to both sides of the equation:

$\displaystyle{5}{{x}}^{{2}}+{7}-{x}+{2}+{3}{{x}}^{{2}}={x}-{2}-{3}{{x}}^{{2}}-{x}+{2}+{3}{{x}}^{{2}}\usepackage{cmbright}\Huge\$

$\displaystyle{8}{{x}}^{{2}}-{x}+{9}={0}\usepackage{cmbright}\Huge\$

The value of $\displaystyle{a}={8}\usepackage{cmbright}\Huge\$ , the coefficient of the $\displaystyle{{x}}^{{2}}\usepackage{cmbright}\Huge\$ term.