Incorrect. Rewrite in standard form by subtracting $\displaystyle{12}{x}-{23}\usepackage{cmbright}\Huge\$ from both sides: $\displaystyle{{x}}^{{2}}-{10}{x}+{24}={0}\usepackage{cmbright}\Huge\$

Then use the Quadratic Formula, $\displaystyle{x}=\frac{{-{b}\pm\sqrt{{{{b}}^{{2}}-{4}{a}{c}}}}}{{{2}{a}}}\usepackage{cmbright}\Huge\$ , with $\displaystyle{a}={1},{b}=-{10}\usepackage{cmbright}\Huge\$ , and $\displaystyle{c}={24}\usepackage{cmbright}\Huge\$ .