You probably recognized that $\displaystyle{a}={1},{b}={5}\usepackage{cmbright}\Huge\$ , and $\displaystyle{c}={2}\usepackage{cmbright}\Huge\$ . But instead of precisely using the Quadratic Formula, $\displaystyle{x}=\frac{{-{b}\pm\sqrt{{{{b}}^{{2}}-{4}{a}{c}}}}}{{{2}{a}}}\usepackage{cmbright}\Huge\$ , you found $\displaystyle{x}=-{b}\pm\frac{\sqrt{{{{b}}^{{2}}-{4}{a}{c}}}}{{{2}{a}}}\usepackage{cmbright}\Huge\$