Incorrect. In this equation, $\displaystyle{a}={5},{b}={15}\usepackage{cmbright}\Huge\$ , and $\displaystyle{c}={11}\usepackage{cmbright}\Huge\$ . Compute $\displaystyle{{b}}^{{2}}-{4}{a}{c}\usepackage{cmbright}\Huge\$ . If the result is a positive number, there are two real solutions. If the result is 0, there is one real solution. If the result is negative, there are no real solutions. (There are two complex solutions.)