Correct. In this equation, $\displaystyle{a}={9},{b}=-{12}\usepackage{cmbright}\Huge\$ , and $\displaystyle{c}={4}\usepackage{cmbright}\Huge\$ . Therefore,

$\displaystyle{{b}}^{{2}}-{4}{a}{c}={{\left(-{12}\right)}}^{{2}}-{4}{\left({9}\right)}{\left({4}\right)}={144}-{144}={0}\usepackage{cmbright}\Huge\$

Because the discriminant is 0, there is one real solution.