You correctly chose a function whose graph would begin at $\displaystyle{\left(-{2},{1}\right)}\usepackage{cmbright}\Huge\$ . However, $\displaystyle{f{{\left({x}\right)}}}={1}+{3}\sqrt{{{x}+{2}}}\usepackage{cmbright}\Huge\$ increases as x increases, so its graph would go up. The given graph goes down, so the radical needs to be multiplied by a negative number.