You correctly identified that the function will decrease. However, $\displaystyle{f{{\left({1}\right)}}}={1}-\sqrt{{{1}-{1}}}={1}-\sqrt{{0}}={1}\usepackage{cmbright}\Huge\$ , so the graph will begin at $\displaystyle{\left({1},{1}\right)}\usepackage{cmbright}\Huge\$ . The correct answer is: Yes, because it will begin at (1, 1) and decrease without bound.