This expression is equivalent to $\displaystyle{\left({3}-{5}{i}\right)}{\left(-{2}{i}\right)}\usepackage{cmbright}\Huge\$ .

$\displaystyle{\left({3}-{5}{i}\right)}{\left(-{2}{i}\right)}={\left({3}\right)}{\left(-{2}{i}\right)}-{\left({5}{i}\right)}{\left(-{2}{i}\right)}=-{6}{i}-{\left(-{10}{{i}}^{{2}}\right)}=-{6}{i}+{10}{{i}}^{{2}}\usepackage{cmbright}\Huge\$

The correct answer is $\displaystyle{10}+{6}{i}\usepackage{cmbright}\Huge\$ .