Entering the value $\displaystyle-{6}\usepackage{cmbright}\Huge\$ in the table will create a relation in which the input $\displaystyle-{6}\usepackage{cmbright}\Huge\$ has two outputs: $\displaystyle-{8}\usepackage{cmbright}\Huge\$ and 2. Because there is an input with more than one output, this relation is not a function. The correct answer is 0.