Correct. The slope of the line $\displaystyle{y}+{1}=\frac{{3}}{{4}}{\left({x}-{2}\right)}\usepackage{cmbright}\Huge\$ is $\displaystyle\frac{{3}}{{4}}\usepackage{cmbright}\Huge\$ , so any line parallel to it will also have a slope of $\displaystyle\frac{{3}}{{4}}\usepackage{cmbright}\Huge\$ . Neither of the line choices has a slope of $\displaystyle\frac{{3}}{{4}}\usepackage{cmbright}\Huge\$ , so neither line is parallel to $\displaystyle{y}+{1}=\frac{{3}}{{4}}{\left({x}-{2}\right)}\usepackage{cmbright}\Huge\$ .