You correctly identified that the graph of the function will begin at $\displaystyle{\left(-{1},{1}\right)}\usepackage{cmbright}\Huge\$ , but you may have forgotten that a positive sign in front of the square root means the graph will go up. The correct answer is: No, because it will begin at $\displaystyle{\left(-{1},{1}\right)}\usepackage{cmbright}\Huge\$ and increase without bound.