You correctly identified that the function will increase. However, $\displaystyle{f{{\left(-{1}\right)}}}={1}+\sqrt{{-{1}+{1}}}={1}+\sqrt{{0}}={1}\usepackage{cmbright}\Huge\$ , so the graph will begin at $\displaystyle{\left(-{1},{1}\right)}\usepackage{cmbright}\Huge\$ . The correct answer is: No, because it will begin at $\displaystyle{\left(-{1},{1}\right)}\usepackage{cmbright}\Huge\$ and increase without bound.