Correct. Use the quotient property, followed by the power property: $\displaystyle{\log}_{{{2}}}\frac{{{{64}}^{{x}}}}{{y}}={\log}_{{{2}}}{\left({{64}}^{{x}}\right)}-{\log}_{{{2}}}{y}={x}{\log}_{{{2}}}{64}-{\log}_{{{2}}}{y}={6}{x}-{\log}_{{{2}}}{y}\usepackage{cmbright}\Huge\$