Correct. The principal $\displaystyle{P}={10},{000}\usepackage{cmbright}\Huge\$ , the interest rate $\displaystyle{r}={0.005}\usepackage{cmbright}\Huge\$ , the number of compounding periods $\displaystyle{m}={2}\usepackage{cmbright}\Huge\$ , and the time $\displaystyle{t}={4}\usepackage{cmbright}\Huge\$ . Substituting gives you:

$\displaystyle{A}={10},{000}{{\left({1}+\frac{{0.005}}{{2}}\right)}}^{{{2}\cdot{4}}}={10},{000}{{\left({1}+{0.0025}\right)}}^{{8}}\approx{10},{000}{\left({1.0201759}\right)}\usepackage{cmbright}\Huge\$

$\displaystyle={10201.759}\approx{10201.76}\usepackage{cmbright}\Huge\$