Incorrect. Use the product property: $\displaystyle{\log}_{{b}}{\left({M}{N}\right)}={\log}_{{b}}{M}+{\log}_{{b}}{N}\usepackage{cmbright}\Huge\$

This will give you: $\displaystyle{\log}_{{{2}}}{\left({32}\cdot{64}\right)}={\log}_{{{2}}}{32}+{\log}_{{{2}}}{64}\usepackage{cmbright}\Huge\$

Rewrite 32 and 64 as powers of 2 and use the definition of logarithm to simplify further. The correct answer is 11.