Natural logarithms have a base of e. Rewrite the equation: $\displaystyle{\log}_{{{e}}}{2}{x}={3.25}\usepackage{cmbright}\Huge\$

Change to an exponential equation: $\displaystyle{2}{x}={{e}}^{{{3.25}}}\usepackage{cmbright}\Huge\$

Solve for x: $\displaystyle{x}=\frac{{1}}{{2}}{{e}}^{{{3.25}}}\usepackage{cmbright}\Huge\$