It appears that you tried to simplify by first dividing both sides by $\displaystyle{\ln{{2}}}\usepackage{cmbright}\Huge\$ . However, $\displaystyle{\ln{{2}}}{x}\usepackage{cmbright}\Huge\$ is not the same as $\displaystyle{\ln{{2}}}\cdot{x}\usepackage{cmbright}\Huge\$ . The expression $\displaystyle{\ln{{2}}}{x}\usepackage{cmbright}\Huge\$ tells you to multiply x by 2 and then compute a logarithm. So $\displaystyle{\ln{{2}}}\usepackage{cmbright}\Huge\$ is not a factor of $\displaystyle{\ln{{2}}}{x}\usepackage{cmbright}\Huge\$ . You should first rewrite the given equation in exponential form, keeping in mind that a natural logarithm has a base of e.