Correct. Find the intensity of noise for a whisper and a normal conversation:

$\displaystyle{30}={10}\cdot{\log{{\left(\frac{{w}}{{P}_{{0}}}\right)}}}\usepackage{cmbright}\Huge\$ and $\displaystyle{64}={10}\cdot{\log{{\left(\frac{{c}}{{P}_{{0}}}\right)}}}\usepackage{cmbright}\Huge\$

Divide both equations by 10: $\displaystyle{3}={\log{{\left(\frac{{w}}{{P}_{{0}}}\right)}}}\usepackage{cmbright}\Huge\$ and $\displaystyle{6.4}={\log{{\left(\frac{{c}}{{P}_{{0}}}\right)}}}\usepackage{cmbright}\Huge\$

Rewrite the equations as exponential equations: $\displaystyle{{10}}^{{3}}=\frac{{w}}{{P}_{{0}}}\usepackage{cmbright}\Huge\$ and $\displaystyle{{10}}^{{6.4}}=\frac{{c}}{{P}_{{0}}}\usepackage{cmbright}\Huge\$

Multiply both sides of the equations by $\displaystyle{P}_{{0}}\usepackage{cmbright}\Huge\$ : $\displaystyle{w}={{10}}^{{3}}{P}_{{0}}\usepackage{cmbright}\Huge\$ and $\displaystyle{c}={{10}}^{{6.4}}{P}_{{0}}\usepackage{cmbright}\Huge\$

Divide to compare the two noises: $\displaystyle\frac{{c}}{{w}}=\frac{{{{10}}^{{6.4}}{P}_{{0}}}}{{{{10}}^{{3}}{P}_{{0}}}}={{10}}^{{3.4}}\usepackage{cmbright}\Huge\$

Using a calculator, you will find that a conversation is about 2,511.89 times as strong as a whisper.