Correct. Because A is 100 times as large as $\displaystyle{A}_{{0}}\usepackage{cmbright}\Huge\$ , $\displaystyle{A}={100}{A}_{{0}}\usepackage{cmbright}\Huge\$ . Substitute this expression in for A.

$\displaystyle{R}={\log{{\left(\frac{{{100}{A}_{{0}}}}{{A}_{{0}}}\right)}}}={\log{{100}}}\usepackage{cmbright}\Huge\$

Now $\displaystyle{{10}}^{{2}}={100}\usepackage{cmbright}\Huge\$ , so $\displaystyle{\log{{100}}}={2}\usepackage{cmbright}\Huge\$ and $\displaystyle{R}={2}\usepackage{cmbright}\Huge\$ .