Correct. Since the graphed line has slope $\displaystyle-\frac{{1}}{{3}}\usepackage{cmbright}\Huge\$ (it goes through the points (0, 3) and (3, 2)), any line perpendicular to it will have slope 3 (the opposite reciprocal of $\displaystyle-\frac{{1}}{{3}}\usepackage{cmbright}\Huge\$ ).